JavaScript weekday list get

All we need is an easy explanation of the problem, so here it is.

I need to create a JavaScript function for the below requirements. I need to get every week day date list. If you know nodeJs package tell me that. Thank you for your attention.

Example - 
 2022-01-03
 2022-01-04
 2022-01-05
 2022-01-06
 2022-01-07

 2022-01-10
 2022-01-11
 2022-01-12
 2022-01-13
 2022-01-14 
 ..........
 ..........
 until year-end

like this pattern (only Monday to Friday)

How to solve :

I know you bored from this bug, So we are here to help you! Take a deep breath and look at the explanation of your problem. We have many solutions to this problem, But we recommend you to use the first method because it is tested & true method that will 100% work for you.

Method 1

function getWeekDaysForYear(year) {
  const isLeap = year % 4 === 0;
  const numberOfDays = isLeap ? 366 : 365;
  let currentDate = new Date(Date.UTC(year, 0, 0, 0, 0, 0, 0));

  const weekDays = [];

  for(let i = 1; i <= numberOfDays; i++) {
    currentDate = new Date(currentDate.getTime() + 24 * 3600 * 1000);
    if (currentDate.getDay() === 0 || currentDate.getDay() === 6) {
      continue;
    }
    weekDays.push(currentDate.toISOString().split('T')[0]);
  }

  return weekDays;
}

console.log(getWeekDaysForYear(2022));

This is a simple function which returns all the weekdays for the specified year in an array.

Method 2

JavaScript’s Date object overflows, so you can use:

for (i=1;i<366;i++) {
if (i%7==1 || i%7==2) continue;
const d = new Date(2022, 0, i);
document.write(d.toDateString(),'<br>');
}

You will need to watch for leap years, and recalculate which days are the weekend every year.

Method 3

Something like this

const endDate = new Date(2022,1,2);
const date = new Date(); //today

while (endDate > date) {
  const weekDay = date.getDay();
  if (weekDay != 6 && weekDay != 0) {
    let year = new Intl.DateTimeFormat('en', { year: 'numeric' }).format(date);
    let month = new Intl.DateTimeFormat('en', { month: '2-digit' }).format(date);
    let day = new Intl.DateTimeFormat('en', { day: '2-digit' }).format(date);
    console.log(`${year}-${month}-${day}`);
  }
  date.setDate(date.getDate() + 1);
}

Method 4

Since we’re play code golf…

function getWeekDays(year) {
  // Start on 1 Jan of given year
  let d = new Date(Date.UTC(year, 0));
  let result = [];
  do {
    // Only push dates that aren't Sat (6) or Sun (0)
    d.getDay() % 6 ? result.push(d.toLocaleDateString('en-CA')) : null;
    // Increment date
    d.setDate(d.getDate() + 1);
  // Until get to 1 Jan again
  } while (d.getMonth() + d.getDate() > 1)
  return result;
}

console.log(getWeekDays(new Date().getFullYear()))

Method 5

function getWeekDaysForDateRange(start, end) {
  const [startYear, startMonth, startDate] = start.split("-");
  const [endYear, endMonth, endDate] = end.split("-");
  let beginDate = new Date(Date.UTC(startYear, startMonth - 1, startDate - 1, 0, 0, 0, 0));
  let closeDate = new Date(Date.UTC(endYear, endMonth - 1, endDate, 0, 0, 0, 0));

  const weekDays = [];

  while(beginDate.getTime() !== closeDate.getTime()) {
    beginDate = new Date(beginDate.getTime() + 24 * 3600 * 1000);
    if (beginDate.getDay() === 0 || beginDate.getDay() === 6) {
      continue;
    }
    weekDays.push(beginDate.toISOString().split('T')[0]);
  }
  return weekDays;
}

console.log(getWeekDaysForDateRange('2022-01-01', '2022-01-10'));

Something like this would work for date range as you want!

Note: Use and implement method 1 because this method fully tested our system.
Thank you 🙂

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0