All we need is an easy explanation of the problem, so here it is.
I want a query to select 2 rows for every NumberId from the table that occur without being interrupted by another NumberId, and same for another NumberId and so on
ID Name NumberId
---------------------------
1 Abc 1
2 bcd 1
3 cde 1
4 def 2
5 efg 2
6 fgh 2
7 ghij 2
8 defg 1
9 efgj 1
10 fghi 1
11 ghij 1
I want to select 2 rows from NumberId 1
and 2 rows from NumberId 2
and again 2 rows from NumberId 1
How to solve :
I know you bored from this bug, So we are here to help you! Take a deep breath and look at the explanation of your problem. We have many solutions to this problem, But we recommend you to use the first method because it is tested & true method that will 100% work for you.
Method 1
Try this.
--set up demo data
declare @T table (id int, name varchar(10), NumberId int)
insert into @T(id, name, NumberId) values
(1,'Abc',1),
(2,'bcd',1),
(3,'cde',1),
(4,'def',2),
(5,'efg',2),
(6,'fgh',2),
(7,'ghij',2),
(8,'defg',1),
(9,'efgj',1),
(10,'fghi',1),
(11,'ghij',1 )
;
I used a common table expression to create groupings of consecutive NumberId’s
–Create a grouping for consecutive values called grp
;WITH _cte
AS (
SELECT *
,DATEADD(DAY, - ROW_NUMBER() OVER (
PARTITION BY Numberid ORDER BY [id]
), [id]) AS grp
FROM @T
)
select * from _cte
| id | name | NumberId | grp |
|----|------|----------|-------------------------|
| 1 | Abc | 1 | 1900-01-01 00:00:00.000 |
| 2 | bcd | 1 | 1900-01-01 00:00:00.000 |
| 3 | cde | 1 | 1900-01-01 00:00:00.000 |
| 4 | def | 2 | 1900-01-04 00:00:00.000 |
| 5 | efg | 2 | 1900-01-04 00:00:00.000 |
| 6 | fgh | 2 | 1900-01-04 00:00:00.000 |
| 7 | ghij | 2 | 1900-01-04 00:00:00.000 |
| 8 | defg | 1 | 1900-01-05 00:00:00.000 |
| 9 | efgj | 1 | 1900-01-05 00:00:00.000 |
| 10 | fghi | 1 | 1900-01-05 00:00:00.000 |
| 11 | ghij | 1 | 1900-01-05 00:00:00.000 |
Then, I used another common table expression to add a row_number to each row in the above result
;WITH _cte
AS (
SELECT *
,DATEADD(DAY, - ROW_NUMBER() OVER (
PARTITION BY Numberid ORDER BY [id]
), [id]) AS grp
FROM @T
)
select * from _cte order by id
,AddedRn --add a row number for each entry in the group
AS (
SELECT *
,ROW_NUMBER() OVER (
PARTITION BY grp ORDER BY id
) AS rn
FROM _cte
)
| id | name | NumberId | grp | rn |
|----|------|----------|-------------------------|----|
| 1 | Abc | 1 | 1900-01-01 00:00:00.000 | 1 |
| 2 | bcd | 1 | 1900-01-01 00:00:00.000 | 2 |
| 3 | cde | 1 | 1900-01-01 00:00:00.000 | 3 |
| 4 | def | 2 | 1900-01-04 00:00:00.000 | 1 |
| 5 | efg | 2 | 1900-01-04 00:00:00.000 | 2 |
| 6 | fgh | 2 | 1900-01-04 00:00:00.000 | 3 |
| 7 | ghij | 2 | 1900-01-04 00:00:00.000 | 4 |
| 8 | defg | 1 | 1900-01-05 00:00:00.000 | 1 |
| 9 | efgj | 1 | 1900-01-05 00:00:00.000 | 2 |
| 10 | fghi | 1 | 1900-01-05 00:00:00.000 | 3 |
| 11 | ghij | 1 | 1900-01-05 00:00:00.000 | 4 |
Now put it all together and only select rows where rn
in (1,2)
--set up demo data
declare @T table (id int, name varchar(10), NumberId int)
insert into @T(id, name, NumberId) values
(1,'Abc',1),
(2,'bcd',1),
(3,'cde',1),
(4,'def',2),
(5,'efg',2),
(6,'fgh',2),
(7,'ghij',2),
(8,'defg',1),
(9,'efgj',1),
(10,'fghi',1),
(11,'ghij',1 )
;
--Create a grouping for consecutive values called grp
WITH _cte
AS (
SELECT *
,DATEADD(DAY, - ROW_NUMBER() OVER (
PARTITION BY Numberid ORDER BY [id]
), [id]) AS grp
FROM @T
)
,AddedRn --add a row number for each entry in the group
AS (
SELECT *
,ROW_NUMBER() OVER (
PARTITION BY grp ORDER BY id
) AS rn
FROM _cte
)
--Select only the rows with rn in (1,2)
SELECT *
FROM AddedRn
WHERE rn IN (1,2)
ORDER BY id
| id | name | NumberId | grp | rn |
|----|------|----------|-------------------------|----|
| 1 | Abc | 1 | 1900-01-01 00:00:00.000 | 1 |
| 2 | bcd | 1 | 1900-01-01 00:00:00.000 | 2 |
| 4 | def | 2 | 1900-01-04 00:00:00.000 | 1 |
| 5 | efg | 2 | 1900-01-04 00:00:00.000 | 2 |
| 8 | defg | 1 | 1900-01-05 00:00:00.000 | 1 |
| 9 | efgj | 1 | 1900-01-05 00:00:00.000 | 2 |
Note: Use and implement method 1 because this method fully tested our system.
Thank you 🙂
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